पायथन और smtplib: oauth2 का उपयोग कर जीमेल के माध्यम से मेल भेज रहा है?

Question

तो मैं smtplib (नीचे लिपि का उपयोग कर) का उपयोग कर जीमेल के माध्यम से मेल भेज सकता हूं और मेल भेज सकता हूं, लेकिन मैं सोच रहा था कि oauth2 का उपयोग करना imaplib जैसा विकल्प था? मैंने oauth के बारे में smtplib प्रलेखन पृष्ठ पर कुछ भी नहीं देखा और मुझे कुछ भी गुगल नहीं मिला है। धन्यवाद।

#! /usr/bin/python 

import smtplib 

to = 'myemailaddress' 
gmail_user = 'myemailaddress' 
gmail_pwd = 'passwd' 
smtpserver = smtplib.SMTP("smtp.gmail.com",587) 
smtpserver.ehlo() 
smtpserver.starttls() 
smtpserver.ehlo 
smtpserver.login(gmail_user, gmail_pwd) 
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n' 
print header 
msg = header + '\n this is test msg from me \n\n' 
smtpserver.sendmail(gmail_user, to, msg) 
print 'done!' 
smtpserver.close(); 

संपादित करें:

धन्यवाद बहुत विस्तृत उसके जवाब में प्रदान की explaination के लिए samy.vilar करने के लिए। हालांकि, मुझे थोड़ा परेशानी हो रही है। यहाँ मेरी स्क्रिप्ट है:

send: 'ehlo test\r\n' 
reply: '250-mx.google.com at your service, [75.173.8.127]\r\n' 
reply: '250-SIZE 35882577\r\n' 
reply: '250-8BITMIME\r\n' 
reply: '250-STARTTLS\r\n' 
reply: '250 ENHANCEDSTATUSCODES\r\n' 
reply: retcode (250); Msg: mx.google.com at your service, [75.173.8.127] 
SIZE 35882577 
8BITMIME 
STARTTLS 
ENHANCEDSTATUSCODES 
send: 'STARTTLS\r\n' 
reply: '220 2.0.0 Ready to start TLS\r\n' 
reply: retcode (220); Msg: 2.0.0 Ready to start TLS 
send: 'AUTH XOAUTH R0VUIGh0dHBzOi8vbWFpbC5nb29nbGUuY29tL21haWwvYi90ZXN0aW5nLm9hdXRoLjFAZ21haWwuY29tL3NtdHAvIG9hdXRoX2JvZHlfaGFzaD0iMmptajdsNXJTdzB5VmIlMkZ2bFdBWWtLJTJGWUJ3ayUzRCIsb2F1dGhfY29uc3VtZXJfa2V5PSJhbm9ueW1vdXMiLG9hdXRoX25vbmNlPSI3Nzc0ODMyIixvYXV0aF9zaWduYXR1cmU9IkxuckZHODdxdHRxZUhsUlQ1emRndmtEZ1UzTSUzRCIsb2F1dGhfc2lnbmF0dXJlX21ldGhvZD0iSE1BQy1TSEExIixvYXV0aF90aW1lc3RhbXA9IjEzNDIxNDI3NzIiLG9hdXRoX3Rva2VuPSIxJTJGTUk2QjJEcUpQNEZFa0RSTFVLckQ1bDQ2c1EwNzU4LTJ1Y0VLQlktRGVCMCIsb2F1dGhfdmVyc2lvbj0iMS4wIg==\r\n' 
reply: '235 2.7.0 Accepted\r\n' 
reply: retcode (235); Msg: 2.7.0 Accepted 

लेकिन तब जब यह ईमेल भेजने के लिए आता है, यह भूल जाते हैं कि conn पहले से ही था लगता है:

#! /usr/bin/python 

import oauth2 as oauth 
import oauth2.clients.smtp as smtplib 

consumer = oauth.Consumer('anonymous', 'anonymous') 
token = oauth.Token('1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0', 'NysqNqVTulFsdHpSRrPP56sF') 

url = "https://mail.google.com/mail/b/testing.oauth.1@gmail.com/smtp/" 

conn = smtplib.SMTP('smtp.googlemail.com', 587) 
conn.set_debuglevel(True) 
conn.ehlo('test') 
conn.starttls() 

conn.authenticate(url, consumer, token) 

header = 'To:testing.oauth.1@gmail.com\n' + 'From: testing.oauth.1@gmail.com\n' + 'Subject:testing \n' 
msg = header + '\n this is test msg from me \n\n' 
conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 

मुझे क्या puzzling है, यह ठीक प्रमाणित करने के लिए प्रकट होता है प्रमाणीकृत:

send: 'ehlo [192.168.2.4]\r\n' 
reply: '250-mx.google.com at your service, [75.173.8.127]\r\n' 
reply: '250-SIZE 35882577\r\n' 
reply: '250-8BITMIME\r\n' 
reply: '250-AUTH LOGIN PLAIN XOAUTH\r\n' 
reply: '250 ENHANCEDSTATUSCODES\r\n' 
reply: retcode (250); Msg: mx.google.com at your service, [75.173.8.127] 
SIZE 35882577 
8BITMIME 
AUTH LOGIN PLAIN XOAUTH 
ENHANCEDSTATUSCODES 
send: 'mail FROM:<testing.oauth.1@gmail.com> size=107\r\n' 
reply: '530-5.5.1 Authentication Required. Learn more at\r\n' 
reply: '530 5.5.1 http://support.google.com/mail/bin/answer.py?answer=14257 tu7sm3163839pbc.55\r\n' 
reply: retcode (530); Msg: 5.5.1 Authentication Required. Learn more at 
5.5.1 http://support.google.com/mail/bin/answer.py?answer=14257 tu7sm3163839pbc.55 
send: 'rset\r\n' 
reply: '250 2.1.5 Flushed tu7sm3163839pbc.55\r\n' 
reply: retcode (250); Msg: 2.1.5 Flushed tu7sm3163839pbc.55 
Traceback (most recent call last): 
    File "./gmail_send3.py", line 47, in <module> 
    conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 
    File "/usr/lib/python2.7/smtplib.py", line 713, in sendmail 
    raise SMTPSenderRefused(code, resp, from_addr) 
smtplib.SMTPSenderRefused: (530, '5.5.1 Authentication Required. Learn more at\n5.5.1 http://support.google.com/mail/bin/answer.py?answer=14257 tu7sm3163839pbc.55', 'testing.oauth.1@gmail.com') 

Answer 1

दिलचस्प, मुझे लगता है कि यह संभव है, मैं निम्नलिखित लिंक
https://developers.google.com/google-apps/gmail/oauth_overviewपाया

अद्यतन
https://github.com/google/gmail-oauth2-tools/wiki/OAuth2DotPyRunThrough
यह OAuth2 का उपयोग कर के माध्यम से नए पैदल दूरी पर है, ऐसा लगता है xoauth तरह अप्रचलित घोषित किया जा रहा है, मैं पुराने संस्करण xoauth.py फ़ाइल प्राप्त करने के लिए URL को अपडेट किसी भी एक अभी भी है, के मामले में इसकी आवश्यकता है, हालांकि ऐसा लगता है कि Google ने अपना एपीआई बदल दिया है और यह walkthrough अब लागू नहीं है।

आप वास्तव में संवाद करने के लिए xoauth या https://github.com/simplegeo/python-oauth2/ का उपयोग कर सकते हैं, मैं बाद वाले को अनुशंसा करता हूं, इसकी अधिक बहुमुखी।

स्पष्ट रूप से आपको पहले xoauth.py स्क्रिप्ट डाउनलोड करने की आवश्यकता है।

$ wget https://raw.githubusercontent.com/google/gmail-oauth2-tools/master/obsolete/python/xoauth.py 
$ python xoauth.py --generate_oauth_token --user=testing.oauth.1@gmail.com 

xoauth.py:74: DeprecationWarning: the sha module is deprecated; use the hashlib module instead 
import sha 
oauth_token_secret: HFJEvjcTfiXSPxgLzDh-1yaH 
oauth_token: 4/EwUxCtY9ye1kdtb4uNJIcaUe9KXl 
oauth_callback_confirmed: true 
To authorize token, visit this url and follow the directions to generate a verification code: 
https://www.google.com/accounts/OAuthAuthorizeToken?oauth_token=4%2FEwUxCtY9ye1kdtb4uNJIcaUe9KXl 
Enter verification code: 7XjT15fqk1aNe8152d9oTRcJ 
oauth_token: 1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0 
oauth_token_secret: NysqNqVTulFsdHpSRrPP56sF 

परीक्षण करने देता है:

$ python xoauth.py --test_imap_authentication --user=testing.oauth.1@gmail.com \ 
--oauth_token=1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0 --oauth_token_secret=NysqNqVTulFsdHpSRrPP56sF 

xoauth.py:74: DeprecationWarning: the sha module is deprecated; use the hashlib module instead 
xoauth string (before base64-encoding): 
GET https://mail.google.com/mail/b/testing.oauth.1@gmail.com/imap/ oauth_consumer_key="anonymous",oauth_nonce="18010070659685102619",oauth_signature="jTJv%2FAFATpzfq%2BZTLAAxFNmWPi0%3D",oauth_signature_method="HMAC-SHA1",oauth_timestamp="1342084141",oauth_token="1%2FMI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0",oauth_version="1.0" 

XOAUTH string (base64-encoded): R0VUIGh0dHBzOi8vbWFpbC5nb29nbGUuY29tL21haWwvYi90ZXN0aW5nLm9hdXRoLjFAZ21haWwuY29tL2ltYXAvIG9hdXRoX2NvbnN1bWVyX2tleT0iYW5vbnltb3VzIixvYXV0aF9ub25jZT0iMTgwMTAwNzA2NTk2ODUxMDI2MTkiLG9hdXRoX3NpZ25hdHVyZT0ialRKdiUyRkFGQVRwemZxJTJCWlRMQUF4Rk5tV1BpMCUzRCIsb2F1dGhfc2lnbmF0dXJlX21ldGhvZD0iSE1BQy1TSEExIixvYXV0aF90aW1lc3RhbXA9IjEzNDIwODQxNDEiLG9hdXRoX3Rva2VuPSIxJTJGTUk2QjJEcUpQNEZFa0RSTFVLckQ1bDQ2c1EwNzU4LTJ1Y0VLQlktRGVCMCIsb2F1dGhfdmVyc2lvbj0iMS4wIg== 

09:01.40 > COKI1 AUTHENTICATE XOAUTH 
09:01.44 < + 
09:01.45 write literal size 444 
09:02.68 < * CAPABILITY IMAP4rev1 UNSELECT IDLE NAMESPACE QUOTA ID XLIST CHILDREN X-GM-EXT-1 UIDPLUS COMPRESS=DEFLATE 
09:02.68 < COKI1 OK testing.oauth.1@gmail.com Testing Oauth authenticated (Success) 
09:02.68 > COKI2 SELECT INBOX 
09:03.09 < * FLAGS (\Answered \Flagged \Draft \Deleted \Seen) 
09:03.09 < * OK [PERMANENTFLAGS (\Answered \Flagged \Draft \Deleted \Seen \*)] Flags permitted. 
09:03.09 < * OK [UIDVALIDITY 3] UIDs valid. 
09:03.09 < * 3 EXISTS 
09:03.09 < * 0 RECENT 
09:03.09 < * OK [UIDNEXT 4] Predicted next UID. 
09:03.09 < COKI2 OK [READ-WRITE] INBOX selected. (Success) 

लगता है कि हम जाने के लिए अच्छे हैं। आप एक virtualenv

$ git clone https://github.com/simplegeo/python-oauth2.git 
$ cd python-oauth2/ 
$ sudo python setup.py install 

स्थापित करना चाहते हैं और डॉक्स से सही ले लिया हो सकता है:

import oauth2 as oauth 
import oauth2.clients.imap as imaplib 

# Set up your Consumer and Token as per usual. Just like any other 
# three-legged OAuth request. 
consumer = oauth.Consumer('anonymous', 'anonymous') 
token = oauth.Token('1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0', 'NysqNqVTulFsdHpSRrPP56sF') 

# Setup the URL according to Google's XOAUTH implementation. Be sure 
# to replace the email here with the appropriate email address that 
# you wish to access. 
url = "https://mail.google.com/mail/b/testing.oauth.1@gmail.com/imap/" 

conn = imaplib.IMAP4_SSL('imap.googlemail.com') 
conn.debug = 4 

# This is the only thing in the API for impaplib.IMAP4_SSL that has 
# changed. You now authenticate with the URL, consumer, and token. 
conn.authenticate(url, consumer, token) 

# Once authenticated everything from the impalib.IMAP4_SSL class will 
# work as per usual without any modification to your code. 
conn.select('INBOX') 
print conn.list() 


>>> conn.authenticate(url, consumer, token) 
20:11.73 > EPKK1 AUTHENTICATE XOAUTH 
20:11.78 < + 
20:11.78 write literal size 496 
20:11.93 < * CAPABILITY IMAP4rev1 UNSELECT IDLE NAMESPACE QUOTA ID XLIST CHILDREN X-GM-EXT-1 UIDPLUS COMPRESS=DEFLATE 
20:11.93 < EPKK1 OK testing.oauth.1@gmail.com Testing Oauth authenticated (Success) 
>>> conn.select('INBOX') 
20:17.47 > EPKK2 SELECT INBOX 
20:17.58 < * FLAGS (\Answered \Flagged \Draft \Deleted \Seen) 
20:17.58 < * OK [PERMANENTFLAGS (\Answered \Flagged \Draft \Deleted \Seen \*)] Flags permitted. 
20:17.58 < * OK [UIDVALIDITY 3] UIDs valid. 
20:17.58 < * 3 EXISTS 
20:17.58 < * 0 RECENT 
20:17.58 < * OK [UIDNEXT 4] Predicted next UID. 
20:17.58 < EPKK2 OK [READ-WRITE] INBOX selected. (Success) 
('OK', ['3']) 
>>> print conn.list() 
20:20.23 > EPKK3 LIST "" * 
20:20.28 < * LIST (\HasNoChildren) "/" "INBOX" 
20:20.28 < * LIST (\Noselect \HasChildren) "/" "[Gmail]" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/All Mail" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/Drafts" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/Important" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/Sent Mail" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/Spam" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/Starred" 
20:20.28 < * LIST (\HasNoChildren) "/" "[Gmail]/Trash" 
20:20.28 < EPKK3 OK Success 
('OK', ['(\\HasNoChildren) "/" "INBOX"', '(\\Noselect \\HasChildren) "/" "[Gmail]"', '(\\HasNoChildren) "/" "[Gmail]/All Mail"', '(\\HasNoChildren) "/" "[Gmail]/Drafts"', '(\\HasNoChildren) "/" "[Gmail]/Important"', '(\\HasNoChildren) "/" "[Gmail]/Sent Mail"', '(\\HasNoChildren) "/" "[Gmail]/Spam"', '(\\HasNoChildren) "/" "[Gmail]/Starred"', '(\\HasNoChildren) "/" "[Gmail]/Trash"']) 
>>> 

smtp के लिए

:

import oauth2 as oauth 
import oauth2.clients.smtp as smtplib 

# Set up your Consumer and Token as per usual. Just like any other 
# three-legged OAuth request. 
# Set up your Consumer and Token as per usual. Just like any other 
# three-legged OAuth request. 
consumer = oauth.Consumer('anonymous', 'anonymous') 
token = oauth.Token('1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0', 'NysqNqVTulFsdHpSRrPP56sF') 

# Setup the URL according to Google's XOAUTH implementation. Be sure 
# to replace the email here with the appropriate email address that 
# you wish to access. 
url = "https://mail.google.com/mail/b/testing.oauth.1@gmail.com/smtp/" 

conn = smtplib.SMTP('smtp.googlemail.com', 587) 
conn.set_debuglevel(True) 
conn.ehlo('test') 
conn.starttls() 

# Again the only thing modified from smtplib.SMTP is the authenticate 
# method, which works identically to the imaplib.IMAP4_SSL method. 
conn.authenticate(url, consumer, token) 



>>> conn.ehlo('test') 
send: 'ehlo test\r\n' 
reply: '250-mx.google.com at your service, [142.255.57.49]\r\n' 
reply: '250-SIZE 35882577\r\n' 
reply: '250-8BITMIME\r\n' 
reply: '250-STARTTLS\r\n' 
reply: '250 ENHANCEDSTATUSCODES\r\n' 
reply: retcode (250); Msg: mx.google.com at your service, [142.255.57.49] 
SIZE 35882577 
8BITMIME 
STARTTLS 
ENHANCEDSTATUSCODES 
(250, 'mx.google.com at your service, [142.255.57.49]\nSIZE 35882577\n8BITMIME\nSTARTTLS\nENHANCEDSTATUSCODES') 
>>> conn.starttls() 
send: 'STARTTLS\r\n' 
reply: '220 2.0.0 Ready to start TLS\r\n' 
reply: retcode (220); Msg: 2.0.0 Ready to start TLS 
(220, '2.0.0 Ready to start TLS') 
>>> conn.authenticate(url, consumer, token) 
send: 'AUTH XOAUTH R0VUIGh0dHBzOi8vbWFpbC5nb29nbGUuY29tL21haWwvYi90ZXN0aW5nLm9hdXRoLjFAZ21haWwuY29tL3NtdHAvIG9hdXRoX2JvZHlfaGFzaD0iMmptajdsNXJTdzB5VmIlMkZ2bFdBWWtLJTJGWUJ3ayUzRCIsb2F1dGhfY29uc3VtZXJfa2V5PSJhbm9ueW1vdXMiLG9hdXRoX25vbmNlPSI4MTEyMDkxNCIsb2F1dGhfc2lnbmF0dXJlPSJSaUFsTGdQWnpBSkNQJTJGWmx5aGRpYU1CV0xiTSUzRCIsb2F1dGhfc2lnbmF0dXJlX21ldGhvZD0iSE1BQy1TSEExIixvYXV0aF90aW1lc3RhbXA9IjEzNDIwODU2NzIiLG9hdXRoX3Rva2VuPSIxJTJGTUk2QjJEcUpQNEZFa0RSTFVLckQ1bDQ2c1EwNzU4LTJ1Y0VLQlktRGVCMCIsb2F1dGhfdmVyc2lvbj0iMS4wIg==\r\n' 
reply: '235 2.7.0 Accepted\r\n' 
reply: retcode (235); Msg: 2.7.0 Accepted 
>>> 

और भेजने के लिए ईमेल:

>>> conn.authenticate(url, consumer, token) 
send: 'AUTH XOAUTH R0VUIGh0dHBzOi8vbWFpbC5nb29nbGUuY29tL21haWwvYi90ZXN0aW5nLm9hdXRoLjFAZ21haWwuY29tL3NtdHAvIG9hdXRoX2JvZHlfaGFzaD0iMmptajdsNXJTdzB5VmIlMkZ2bFdBWWtLJTJGWUJ3ayUzRCIsb2F1dGhfY29uc3VtZXJfa2V5PSJhbm9ueW1vdXMiLG9hdXRoX25vbmNlPSI2OTg3ODM3NiIsb2F1dGhfc2lnbmF0dXJlPSIlMkZjUGslMkJRVWVJY1RaYXp1ekkwR1FzdkdtbDFBJTNEIixvYXV0aF9zaWduYXR1cmVfbWV0aG9kPSJITUFDLVNIQTEiLG9hdXRoX3RpbWVzdGFtcD0iMTM0MjA4NjAxNCIsb2F1dGhfdG9rZW49IjElMkZNSTZCMkRxSlA0RkVrRFJMVUtyRDVsNDZzUTA3NTgtMnVjRUtCWS1EZUIwIixvYXV0aF92ZXJzaW9uPSIxLjAi\r\n' 
reply: '235 2.7.0 Accepted\r\n' 
reply: retcode (235); Msg: 2.7.0 Accepted 
>>> header = 'To:testing.oauth.1@gmail.com\n' + 'From: testing.oauth.1@gmail.com\n' + 'Subject:testing \n' 
>>> msg = header + '\n this is test msg from me \n\n' 
>>> conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 
send: 'mail FROM:<testing.oauth.1@gmail.com> size=107\r\n' 
reply: '250 2.1.0 OK gb7sm6540492qab.12\r\n' 
reply: retcode (250); Msg: 2.1.0 OK gb7sm6540492qab.12 
send: 'rcpt TO:<testing.oauth.1@gmail.com>\r\n' 
reply: '250 2.1.5 OK gb7sm6540492qab.12\r\n' 
reply: retcode (250); Msg: 2.1.5 OK gb7sm6540492qab.12 
send: 'data\r\n' 
reply: '354 Go ahead gb7sm6540492qab.12\r\n' 
reply: retcode (354); Msg: Go ahead gb7sm6540492qab.12 
data: (354, 'Go ahead gb7sm6540492qab.12') 
send: 'To:testing.oauth.1@gmail.com\r\nFrom: testing.oauth.1@gmail.com\r\nSubject:testing \r\n\r\n this is test msg from me \r\n\r\n.\r\n' 
reply: '250 2.0.0 OK 1342086030 gb7sm6540492qab.12\r\n' 
reply: retcode (250); Msg: 2.0.0 OK 1342086030 gb7sm6540492qab.12 
data: (250, '2.0.0 OK 1342086030 gb7sm6540492qab.12') 
{} 
>>> 

सुनिश्चित करें कि आप ईमेल भेजने से पहले प्रमाणित करते हैं।
आशा है कि यह मदद करता है ...

अद्यतन
एक बग है कि फिर से प्रमाणीकरण की आवश्यकता हो सकती है, निम्नलिखित काम करना चाहिए।

import oauth2 as oauth 
import oauth2.clients.smtp as smtplib 

consumer = oauth.Consumer('anonymous', 'anonymous') 
token = oauth.Token('1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0', 'NysqNqVTulFsdHpSRrPP56sF') 

url = "https://mail.google.com/mail/b/testing.oauth.1@gmail.com/smtp/" 

conn = smtplib.SMTP('smtp.googlemail.com', 587) 
conn.set_debuglevel(True) 
conn.ehlo('test') 
conn.starttls() 

conn.authenticate(url, consumer, token) 

header = 'To:testing.oauth.1@gmail.com\n' + 'From: testing.oauth.1@gmail.com\n' + 'Subject:testing \n' 
msg = header + '\n this is test msg from me \n\n' 
try: 
    conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 
except Exception as ex: 
    print str(ex) 
    print 'retying ...' 
    conn.authenticate(url, consumer, token) 
    conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 

ही आप भी इस तरह के रूप में सीधे xoauth उपयोग कर सकते हैं:

import time 
import smtplib 
import xoauth 

consumer = xoauth.OAuthEntity('anonymous', 'anonymous') 
access_token = xoauth.OAuthEntity('1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0', 'NysqNqVTulFsdHpSRrPP56sF') 

xoauth_string = xoauth.GenerateXOauthString(consumer, access_token, 'testing.oauth.1@gmail.com', 'smtp', 'testing.oauth.1@gmail.com', str(xoauth.random.randrange(2**64 - 1)), str(int(time.time()))) 

smtp_conn = smtplib.SMTP('smtp.gmail.com', 587) 
smtp_conn.set_debuglevel(True) 
smtp_conn.ehlo() 
smtp_conn.starttls() 
smtp_conn.ehlo() 
smtp_conn.docmd('AUTH', 'XOAUTH ' + xoauth.base64.b64encode(xoauth_string)) 

header = 'To:testing.oauth.1@gmail.com\n' + 'From: testing.oauth.1@gmail.com\n' + 'Subject:testing \n' 
msg = header + '\n this is test msg from me \n\n' 
smtp_conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 

इस लगता है हमेशा काम करने के लिए, मैं python-oauth2 टीम के लिए एक टिकट प्रस्तुत करना चाहिए, धन्यवाद।

हालांकि इस पर कभी-भी

import oauth2 as oauth 
import oauth2.clients.smtp as smtplib 

consumer = oauth.Consumer('anonymous', 'anonymous') 
token = oauth.Token('1/MI6B2DqJP4FEkDRLUKrD5l46sQ0758-2ucEKBY-DeB0', 'NysqNqVTulFsdHpSRrPP56sF') 

url = "https://mail.google.com/mail/b/testing.oauth.1@gmail.com/smtp/" 

conn = smtplib.SMTP('smtp.googlemail.com', 587) 
conn.set_debuglevel(True) 
conn.ehlo('test') 
conn.starttls() 
conn.ehlo() 
conn.authenticate(url, consumer, token) 
header = 'To:testing.oauth.1@gmail.com\n' + 'From: testing.oauth.1@gmail.com\n' + 'Subject:testing \n' 
msg = header + '\n this is test msg from me \n\n' 
conn.sendmail('testing.oauth.1@gmail.com', 'testing.oauth.1@gmail.com', msg) 

यह आप के सत्यापन से पहले conn.ehlo() कॉल करने की आवश्यकता लग रहा है कार्य करते हैं।