मैं मल्टीथ्रेडिंग से परिचित हूं और मैंने जावा और ऑब्जेक्टिव-सी में सफलतापूर्वक कई बहुप्रचारित प्रोग्राम विकसित किए हैं। लेकिन मैं एक मुख्य थ्रेड से शामिल होने का उपयोग किए बिना pthreads का उपयोग कर सी में निम्नलिखित को प्राप्त नहीं कर सकता है:प्रबंधक के बिना प्रबंधक/कार्यकर्ता pthreads को सिंक्रनाइज़ करने के लिए कैसे?
मुख्य में():
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#define NUM_OF_THREADS 2
struct thread_data {
int start;
int end;
int *arr;
};
void print(int *ints, int n);
void *processArray(void *args);
int main(int argc, const char * argv[])
{
int numOfInts = 10;
int *ints = malloc(numOfInts * sizeof(int));
for (int i = 0; i < numOfInts; i++) {
ints[i] = i;
}
print(ints, numOfInts); // prints [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
pthread_t threads[NUM_OF_THREADS];
struct thread_data thread_data[NUM_OF_THREADS];
// these vars are used to calculate the index ranges for each thread
int remainingWork = numOfInts, amountOfWork;
int startRange, endRange = -1;
for (int i = 0; i < NUM_OF_THREADS; i++) {
amountOfWork = remainingWork/(NUM_OF_THREADS - i);
startRange = endRange + 1;
endRange = startRange + amountOfWork - 1;
thread_data[i].arr = ints;
thread_data[i].start = startRange;
thread_data[i].end = endRange;
pthread_create(&threads[i], NULL, processArray, (void *)&thread_data[i]);
remainingWork -= amountOfWork;
}
// 1. Signal to the threads to start working
// 2. Wait for them to finish
print(ints, numOfInts); // should print [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
free(ints);
return 0;
}
void *processArray(void *args)
{
struct thread_data *data = (struct thread_data *)args;
int *arr = data->arr;
int start = data->start;
int end = data->end;
// 1. Wait for a signal to start from the main thread
for (int i = start; i <= end; i++) {
arr[i] = arr[i] + 1;
}
// 2. Signal to the main thread that you're done
pthread_exit(NULL);
}
void print(int *ints, int n)
{
printf("[");
for (int i = 0; i < n; i++) {
printf("%d", ints[i]);
if (i+1 != n)
printf(", ");
}
printf("]\n");
}
मैं उपरोक्त कोड में निम्नलिखित प्राप्त करने के लिए चाहते हैं
- काम शुरू करने के लिए धागे पर सिग्नल करें।
- पृष्ठभूमि धागे को समाप्त करने के लिए प्रतीक्षा करें।
processArray() में:
एक संकेत के लिए- प्रतीक्षा मुख्य थ्रेड
- सिग्नल मुख्य थ्रेड कि आपका काम हो गया करने के लिए से शुरू करने के लिए
मुझे नहीं पता मुख्य धागे में शामिल होने का उपयोग करना चाहते हैं क्योंकि the real application में, मुख्य धागा एक बार थ्रेड बना देगा, और फिर यह पृष्ठभूमि थ्रेड को कई बार काम करने के लिए संकेत देगा, और मैं मुख्य थ्रेड को तब तक आगे नहीं बढ़ सकता जब तक कि सभी पृष्ठभूमि thr ईड्स काम खत्म कर दिया है। processArray
समारोह में, मैं निम्नलिखित के रूप में अनंत लूप रखा जाएगा:
void *processArray(void *args)
{
struct thread_data *data = (struct thread_data *)args;
while (1)
{
// 1. Wait for a signal to start from the main thread
int *arr = data->arr;
int start = data->start;
int end = data->end;
// Process
for (int i = start; i <= end; i++) {
arr[i] = arr[i] + 1;
}
// 2. Signal to the main thread that you're done
}
pthread_exit(NULL);
}
ध्यान दें कि मैं सी और POSIX एपीआई के लिए नया हूँ, इसलिए मुझे क्षमा करें यदि मैं कुछ स्पष्ट याद कर रहा हूँ। लेकिन मैंने वास्तव में कई चीजों की कोशिश की, एक म्यूटेक्स, और सेफफोर्स की एक सरणी, और दोनों का मिश्रण, लेकिन सफलता के बिना। मुझे लगता है कि एक शर्त चर मदद कर सकता है, लेकिन मुझे समझ में नहीं आया कि इसका उपयोग कैसे किया जा सकता है।
आपके समय के लिए धन्यवाद।
समस्या हल:
बहुत बहुत शुक्रिया आप लोग! मैं अंत में इसे सुरक्षित रूप से काम करने और आपकी युक्तियों का पालन करके शामिल होने के बिना प्राप्त करने में सक्षम था। यद्यपि समाधान कुछ हद तक बदसूरत है, लेकिन यह काम पूरा हो जाता है और प्रदर्शन लाभ इसके लायक है (जैसा कि आप नीचे देखेंगे)। रुचि किसी के लिए, यह असली आवेदन मैं पर काम कर रहा हूँ, जिसमें मुख्य थ्रेड पृष्ठभूमि धागे को लगातार काम दे रही रखता है के अनुकरण है:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#define NUM_OF_THREADS 5
struct thread_data {
int id;
int start;
int end;
int *arr;
};
pthread_mutex_t currentlyIdleMutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t currentlyIdleCond = PTHREAD_COND_INITIALIZER;
int currentlyIdle;
pthread_mutex_t workReadyMutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t workReadyCond = PTHREAD_COND_INITIALIZER;
int workReady;
pthread_cond_t currentlyWorkingCond = PTHREAD_COND_INITIALIZER;
pthread_mutex_t currentlyWorkingMutex= PTHREAD_MUTEX_INITIALIZER;
int currentlyWorking;
pthread_mutex_t canFinishMutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t canFinishCond = PTHREAD_COND_INITIALIZER;
int canFinish;
void print(int *ints, int n);
void *processArray(void *args);
int validateResult(int *ints, int num, int start);
int main(int argc, const char * argv[])
{
int numOfInts = 10;
int *ints = malloc(numOfInts * sizeof(int));
for (int i = 0; i < numOfInts; i++) {
ints[i] = i;
}
// print(ints, numOfInts);
pthread_t threads[NUM_OF_THREADS];
struct thread_data thread_data[NUM_OF_THREADS];
workReady = 0;
canFinish = 0;
currentlyIdle = 0;
currentlyWorking = 0;
// these vars are used to calculate the index ranges for each thread
int remainingWork = numOfInts, amountOfWork;
int startRange, endRange = -1;
// Create the threads and give each one its data struct.
for (int i = 0; i < NUM_OF_THREADS; i++) {
amountOfWork = remainingWork/(NUM_OF_THREADS - i);
startRange = endRange + 1;
endRange = startRange + amountOfWork - 1;
thread_data[i].id = i;
thread_data[i].arr = ints;
thread_data[i].start = startRange;
thread_data[i].end = endRange;
pthread_create(&threads[i], NULL, processArray, (void *)&thread_data[i]);
remainingWork -= amountOfWork;
}
int loops = 1111111;
int expectedStartingValue = ints[0] + loops; // used to validate the results
// The elements in ints[] should be incremented by 1 in each loop
while (loops-- != 0) {
// Make sure all of them are ready
pthread_mutex_lock(¤tlyIdleMutex);
while (currentlyIdle != NUM_OF_THREADS) {
pthread_cond_wait(¤tlyIdleCond, ¤tlyIdleMutex);
}
pthread_mutex_unlock(¤tlyIdleMutex);
// All threads are now blocked; it's safe to not lock the mutex.
// Prevent them from finishing before authorized.
canFinish = 0;
// Reset the number of currentlyWorking threads
currentlyWorking = NUM_OF_THREADS;
// Signal to the threads to start
pthread_mutex_lock(&workReadyMutex);
workReady = 1;
pthread_cond_broadcast(&workReadyCond);
pthread_mutex_unlock(&workReadyMutex);
// Wait for them to finish
pthread_mutex_lock(¤tlyWorkingMutex);
while (currentlyWorking != 0) {
pthread_cond_wait(¤tlyWorkingCond, ¤tlyWorkingMutex);
}
pthread_mutex_unlock(¤tlyWorkingMutex);
// The threads are now waiting for permission to finish
// Prevent them from starting again
workReady = 0;
currentlyIdle = 0;
// Allow them to finish
pthread_mutex_lock(&canFinishMutex);
canFinish = 1;
pthread_cond_broadcast(&canFinishCond);
pthread_mutex_unlock(&canFinishMutex);
}
// print(ints, numOfInts);
if (validateResult(ints, numOfInts, expectedStartingValue)) {
printf("Result correct.\n");
}
else {
printf("Result invalid.\n");
}
// clean up
for (int i = 0; i < NUM_OF_THREADS; i++) {
pthread_cancel(threads[i]);
}
free(ints);
return 0;
}
void *processArray(void *args)
{
struct thread_data *data = (struct thread_data *)args;
int *arr = data->arr;
int start = data->start;
int end = data->end;
while (1) {
// Set yourself as idle and signal to the main thread, when all threads are idle main will start
pthread_mutex_lock(¤tlyIdleMutex);
currentlyIdle++;
pthread_cond_signal(¤tlyIdleCond);
pthread_mutex_unlock(¤tlyIdleMutex);
// wait for work from main
pthread_mutex_lock(&workReadyMutex);
while (!workReady) {
pthread_cond_wait(&workReadyCond , &workReadyMutex);
}
pthread_mutex_unlock(&workReadyMutex);
// Do the work
for (int i = start; i <= end; i++) {
arr[i] = arr[i] + 1;
}
// mark yourself as finished and signal to main
pthread_mutex_lock(¤tlyWorkingMutex);
currentlyWorking--;
pthread_cond_signal(¤tlyWorkingCond);
pthread_mutex_unlock(¤tlyWorkingMutex);
// Wait for permission to finish
pthread_mutex_lock(&canFinishMutex);
while (!canFinish) {
pthread_cond_wait(&canFinishCond , &canFinishMutex);
}
pthread_mutex_unlock(&canFinishMutex);
}
pthread_exit(NULL);
}
int validateResult(int *ints, int n, int start)
{
int tmp = start;
for (int i = 0; i < n; i++, tmp++) {
if (ints[i] != tmp) {
return 0;
}
}
return 1;
}
void print(int *ints, int n)
{
printf("[");
for (int i = 0; i < n; i++) {
printf("%d", ints[i]);
if (i+1 != n)
printf(", ");
}
printf("]\n");
}
मुझे यकीन है कि हालांकि अगर pthread_cancel
के लिए पर्याप्त है नहीं कर रहा हूँ साफ - सफाई! बाधा के लिए, अगर यह @Jeremy द्वारा उल्लिखित कुछ ओएस तक ही सीमित नहीं था, तो यह बहुत मददगार होगा।
मानक:
मुझे यकीन है कि इनमें से कई की स्थिति वास्तव में एल्गोरिथ्म धीमा नहीं कर रहे हैं बनाना चाहते थे, इसलिए मैं सेटअप इस बेंचमार्क है दो समाधान तुलना करने के लिए:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>
#include <sys/time.h>
#include <sys/resource.h>
#define NUM_OF_THREADS 5
struct thread_data {
int start;
int end;
int *arr;
};
pthread_mutex_t currentlyIdleMutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t currentlyIdleCond = PTHREAD_COND_INITIALIZER;
int currentlyIdle;
pthread_mutex_t workReadyMutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t workReadyCond = PTHREAD_COND_INITIALIZER;
int workReady;
pthread_cond_t currentlyWorkingCond = PTHREAD_COND_INITIALIZER;
pthread_mutex_t currentlyWorkingMutex= PTHREAD_MUTEX_INITIALIZER;
int currentlyWorking;
pthread_mutex_t canFinishMutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t canFinishCond = PTHREAD_COND_INITIALIZER;
int canFinish;
void *processArrayMutex(void *args);
void *processArrayJoin(void *args);
double doItWithMutex(pthread_t *threads, struct thread_data *data, int loops);
double doItWithJoin(pthread_t *threads, struct thread_data *data, int loops);
int main(int argc, const char * argv[])
{
int numOfInts = 10;
int *join_ints = malloc(numOfInts * sizeof(int));
int *mutex_ints = malloc(numOfInts * sizeof(int));
for (int i = 0; i < numOfInts; i++) {
join_ints[i] = i;
mutex_ints[i] = i;
}
pthread_t join_threads[NUM_OF_THREADS];
pthread_t mutex_threads[NUM_OF_THREADS];
struct thread_data join_thread_data[NUM_OF_THREADS];
struct thread_data mutex_thread_data[NUM_OF_THREADS];
workReady = 0;
canFinish = 0;
currentlyIdle = 0;
currentlyWorking = 0;
int remainingWork = numOfInts, amountOfWork;
int startRange, endRange = -1;
for (int i = 0; i < NUM_OF_THREADS; i++) {
amountOfWork = remainingWork/(NUM_OF_THREADS - i);
startRange = endRange + 1;
endRange = startRange + amountOfWork - 1;
join_thread_data[i].arr = join_ints;
join_thread_data[i].start = startRange;
join_thread_data[i].end = endRange;
mutex_thread_data[i].arr = mutex_ints;
mutex_thread_data[i].start = startRange;
mutex_thread_data[i].end = endRange;
pthread_create(&mutex_threads[i], NULL, processArrayMutex, (void *)&mutex_thread_data[i]);
remainingWork -= amountOfWork;
}
int numOfBenchmarkTests = 100;
int numberOfLoopsPerTest= 1000;
double join_sum = 0.0, mutex_sum = 0.0;
for (int i = 0; i < numOfBenchmarkTests; i++)
{
double joinTime = doItWithJoin(join_threads, join_thread_data, numberOfLoopsPerTest);
double mutexTime= doItWithMutex(mutex_threads, mutex_thread_data, numberOfLoopsPerTest);
join_sum += joinTime;
mutex_sum+= mutexTime;
}
double join_avg = join_sum/numOfBenchmarkTests;
double mutex_avg= mutex_sum/numOfBenchmarkTests;
printf("Join average : %f\n", join_avg);
printf("Mutex average: %f\n", mutex_avg);
double diff = join_avg - mutex_avg;
if (diff > 0.0)
printf("Mutex is %.0f%% faster.\n", 100 * diff/join_avg);
else if (diff < 0.0)
printf("Join is %.0f%% faster.\n", 100 * diff/mutex_avg);
else
printf("Both have the same performance.");
free(join_ints);
free(mutex_ints);
return 0;
}
// From https://stackoverflow.com/a/2349941/408286
double get_time()
{
struct timeval t;
struct timezone tzp;
gettimeofday(&t, &tzp);
return t.tv_sec + t.tv_usec*1e-6;
}
double doItWithMutex(pthread_t *threads, struct thread_data *data, int num_loops)
{
double start = get_time();
int loops = num_loops;
while (loops-- != 0) {
// Make sure all of them are ready
pthread_mutex_lock(¤tlyIdleMutex);
while (currentlyIdle != NUM_OF_THREADS) {
pthread_cond_wait(¤tlyIdleCond, ¤tlyIdleMutex);
}
pthread_mutex_unlock(¤tlyIdleMutex);
// All threads are now blocked; it's safe to not lock the mutex.
// Prevent them from finishing before authorized.
canFinish = 0;
// Reset the number of currentlyWorking threads
currentlyWorking = NUM_OF_THREADS;
// Signal to the threads to start
pthread_mutex_lock(&workReadyMutex);
workReady = 1;
pthread_cond_broadcast(&workReadyCond);
pthread_mutex_unlock(&workReadyMutex);
// Wait for them to finish
pthread_mutex_lock(¤tlyWorkingMutex);
while (currentlyWorking != 0) {
pthread_cond_wait(¤tlyWorkingCond, ¤tlyWorkingMutex);
}
pthread_mutex_unlock(¤tlyWorkingMutex);
// The threads are now waiting for permission to finish
// Prevent them from starting again
workReady = 0;
currentlyIdle = 0;
// Allow them to finish
pthread_mutex_lock(&canFinishMutex);
canFinish = 1;
pthread_cond_broadcast(&canFinishCond);
pthread_mutex_unlock(&canFinishMutex);
}
return get_time() - start;
}
double doItWithJoin(pthread_t *threads, struct thread_data *data, int num_loops)
{
double start = get_time();
int loops = num_loops;
while (loops-- != 0) {
// create them
for (int i = 0; i < NUM_OF_THREADS; i++) {
pthread_create(&threads[i], NULL, processArrayJoin, (void *)&data[i]);
}
// wait
for (int i = 0; i < NUM_OF_THREADS; i++) {
pthread_join(threads[i], NULL);
}
}
return get_time() - start;
}
void *processArrayMutex(void *args)
{
struct thread_data *data = (struct thread_data *)args;
int *arr = data->arr;
int start = data->start;
int end = data->end;
while (1) {
// Set yourself as idle and signal to the main thread, when all threads are idle main will start
pthread_mutex_lock(¤tlyIdleMutex);
currentlyIdle++;
pthread_cond_signal(¤tlyIdleCond);
pthread_mutex_unlock(¤tlyIdleMutex);
// wait for work from main
pthread_mutex_lock(&workReadyMutex);
while (!workReady) {
pthread_cond_wait(&workReadyCond , &workReadyMutex);
}
pthread_mutex_unlock(&workReadyMutex);
// Do the work
for (int i = start; i <= end; i++) {
arr[i] = arr[i] + 1;
}
// mark yourself as finished and signal to main
pthread_mutex_lock(¤tlyWorkingMutex);
currentlyWorking--;
pthread_cond_signal(¤tlyWorkingCond);
pthread_mutex_unlock(¤tlyWorkingMutex);
// Wait for permission to finish
pthread_mutex_lock(&canFinishMutex);
while (!canFinish) {
pthread_cond_wait(&canFinishCond , &canFinishMutex);
}
pthread_mutex_unlock(&canFinishMutex);
}
pthread_exit(NULL);
}
void *processArrayJoin(void *args)
{
struct thread_data *data = (struct thread_data *)args;
int *arr = data->arr;
int start = data->start;
int end = data->end;
// Do the work
for (int i = start; i <= end; i++) {
arr[i] = arr[i] + 1;
}
pthread_exit(NULL);
}
और आउटपुट है:
Join average : 0.153074
Mutex average: 0.071588
Mutex is 53% faster.
फिर से धन्यवाद।तुम्हारी मदद के लिए शुक्रिया!
क्षमा करें, आपके प्रश्न को ध्यान से नहीं पढ़ा। आपको क्रमांकित 2 टिप्पणी पर पुन: प्रवेश बाधा लागू करने की आवश्यकता है। Http://pcbec3.ihep.su/~miagkov/code/barrier.c – nhahtdh
@nhahtdh इसके बारे में चिंता न करें। मैं कोड पर एक नज़र डालेगा। धन्यवाद! – Motasim
माइकल बोर ने ऐसा करने के लिए एक मौजूदा कार्य का सुझाव दिया। (मैंने सोचा था कि पोसिक्स ने इसे परिभाषित नहीं किया है, लेकिन यह सब वहाँ है)। – nhahtdh