कनेक्शन org.apache.http.client.ClientProtocolException

Question

देता है मैं सफलतापूर्वक https पर पोस्ट करने के लिए एंड्रॉयड में this solution का इस्तेमाल किया है सर्वर को स्वीकार सभी प्रमाणपत्र

अब मैं में एक ही बात कोशिश कर रहा हूँ सभी प्रमाणपत्रों को स्वीकार करने वाले https सर्वर पर पोस्ट करने के लिए जावा।

मैंने उपरोक्त यूआरएल से EasySSLSocketFactory कक्षा को SocketFactory, LayeredSocketFactory कक्षाओं को httpclient 4.1.2 संस्करण में बहिष्कृत कर दिया है। उपरोक्त यूआरएल से EasyX509TrustManager वर्ग अपरिवर्तित बनी हुई है। यहां EasySSLSocketFactory है जिसे मैंने संशोधित किया है। मैंने उन वर्गों को चिह्नित किया है जिन्हें मैंने संशोधित किया है।

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import java.io.IOException; 
import java.net.InetSocketAddress; 
import java.net.Socket; 
import java.net.UnknownHostException; 

import javax.net.ssl.SSLContext; 
import javax.net.ssl.SSLSocket; 
import javax.net.ssl.TrustManager; 

import org.apache.http.conn.ConnectTimeoutException; 
import org.apache.http.conn.scheme.SchemeSocketFactory; 
import org.apache.http.params.HttpConnectionParams; 
import org.apache.http.params.HttpParams; 


public class EasySSLSocketFactory implements SchemeSocketFactory 
{ 
    private SSLContext sslcontext = null; 

    private static SSLContext createEasySSLContext() throws IOException { 
      try { 
        SSLContext context = SSLContext.getInstance("TLS"); 
        context.init(null, new TrustManager[] { new EasyX509TrustManager(null) }, null); 
        return context; 
      } catch (Exception e) { 
        throw new IOException(e.getMessage()); 
      } 
    } 


    private SSLContext getSSLContext() throws IOException { 
      if (this.sslcontext == null) { 
        this.sslcontext = createEasySSLContext(); 
      } 
      return this.sslcontext; 
    } 

    /** 
     * @see org.apache.http.conn.scheme.SchemeSocketFactory#isSecure(java.net.Socket) 
     */ 
    public boolean isSecure(Socket socket) throws IllegalArgumentException { 
      return true; 
    } 

    // ------------------------------------------------------------------- 
    // javadoc in org.apache.http.conn.scheme.SocketFactory says : 
    // Both Object.equals() and Object.hashCode() must be overridden 
    // for the correct operation of some connection managers 
    // ------------------------------------------------------------------- 

    public boolean equals(Object obj) { 
      return ((obj != null) && obj.getClass().equals(
          EasySSLSocketFactory.class)); 
    } 

    public int hashCode() { 
      return EasySSLSocketFactory.class.hashCode(); 
    } 

    //this method is modified 
    @Override 
    public Socket connectSocket(Socket sock, InetSocketAddress remoteAddress, 
      InetSocketAddress localAddress, HttpParams params) throws IOException, 
      UnknownHostException, ConnectTimeoutException { 

     int connTimeout = HttpConnectionParams.getConnectionTimeout(params); 
     int soTimeout = HttpConnectionParams.getSoTimeout(params); 
     SSLSocket sslsock = (SSLSocket) ((sock != null) ? sock : createSocket(params)); 
     if (localAddress != null) { 
      // we need to bind explicitly 
      sslsock.bind(localAddress); 
    } 

    sslsock.connect(remoteAddress, connTimeout); 
    sslsock.setSoTimeout(soTimeout); 
    return sslsock; 
    } 

    //this method is modified 
    @Override 
    public Socket createSocket(HttpParams arg0) throws IOException { 
     return getSSLContext().getSocketFactory().createSocket(); 
    } 

} 

और यहाँ मेरी httpclient.This वर्ग भी क्योंकि httpclient 4.1.2

public class MyHttpClient extends DefaultHttpClient { 

    /** The time it takes for our client to timeout */ 
    public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds 
    public static final int SOCKET_TIMEOUT = 50 * 1000; // milliseconds 


    public MyHttpClient() { 
    } 

    @Override 
    protected ClientConnectionManager createClientConnectionManager() { 

     SchemeRegistry registry = new SchemeRegistry(); 
     registry.register(new Scheme("http", 80, PlainSocketFactory.getSocketFactory())); 
     // Register for port 443 our SSLSocketFactory to the ConnectionManager 
     registry.register(new Scheme("https", 443, new EasySSLSocketFactory())); 

     //setting the httpparams 
     HttpParams params = new BasicHttpParams(); 
     //params.setParameter(ConnManagerPNames.MAX_TOTAL_CONNECTIONS, 1); 
     //params.setParameter(ConnManagerPNames.MAX_CONNECTIONS_PER_ROUTE, new ConnPerRouteBean(1)); 
     params.setParameter(HttpProtocolParams.USE_EXPECT_CONTINUE, false); 
     //HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1); 
     HttpProtocolParams.setContentCharset(params, "utf8"); 

     return new SingleClientConnManager(registry); 
    } 

} 

मैं निम्नलिखित तरीके से कनेक्ट करने के लिए

ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(); 
     postParameters.add(new BasicNameValuePair("userid", userid)); 
     postParameters.add(new BasicNameValuePair("password", password)); 
     String newresponse = null; 
     BufferedReader in = null; 
     try{ 
      DefaultHttpClient client = new MyHttpClient(); 
      try {   
        HttpPost req = new HttpPost(my https url); 
        UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters); 
        req.setEntity(formEntity); 
        HttpResponse resp = client.execute(req); 
        in = new BufferedReader(new InputStreamReader(resp.getEntity().getContent())); 
        StringBuffer sb = new StringBuffer(""); 
        String line = ""; 
        String NL = System.getProperty("line.separator"); 
        while ((line = in.readLine()) != null) { 
         sb.append(line + NL); 
        } 
        in.close(); 
        newresponse = sb.toString(); 

        }catch(Exception e){ 
         LOGGER.error("Exception", e); 
        }finally { 
         if (in != null) { 
          try { 
           in.close(); 
          } catch (IOException e) { 
           LOGGER.error("IOException: ",e); 
          } 
         } 
        } 
     } catch(Exception e){ 
      LOGGER.debug("Connection Exception: ",e); 
     } 

जब मैं कोशिश कर रहा हूँ का उपयोग कर के संशोधित किया गया है है उपरोक्त तरीके से https सर्वर से कनेक्ट करने का प्रयास करें मुझे

org.apache.http.client.ClientProtocolException 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:822) 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:754) 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:732) 
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:641) 
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 
     at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:304) 
     at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) 
     at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240) 
     at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:164) 
     at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:576) 
     at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164) 
     at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100) 
     at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:563) 
     at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118) 
     at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:399) 
     at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:317) 
     at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:204) 
     at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:182) 
     at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:311) 
     at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) 
     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) 
     at java.lang.Thread.run(Thread.java:662) 
Caused by: org.apache.http.HttpException: Unable to establish route: planned = HttpRoute[{}->https://mysiteurlhere]; current = HttpRoute[{s}->https://mysiteurlhere] 
     at org.apache.http.impl.client.DefaultRequestDirector.establishRoute(DefaultRequestDirector.java:774) 
     at org.apache.http.impl.client.DefaultRequestDirector.tryConnect(DefaultRequestDirector.java:577) 
     at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:425) 
     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:820) 
     ... 22 more 

जिस सर्वर को मैं एक्सेस करने का प्रयास कर रहा हूं वह verisign से प्रमाणपत्र का उपयोग कर रहा है, जो मेरे पास नहीं है। इसलिए मैं सभी प्रमाणपत्र स्वीकार करने की कोशिश कर रहा हूं। भविष्य में मैं इसे बदलने जा रहा हूं।

क्या कोई इसे काम कर सकता है? अग्रिम धन्यवाद।

Answer 1

आपके EasySSLSocketFactory को LayeredSchemeSocketFactory इंटरफ़ेस को भी लागू करना होगा यदि आप इसे एसएसएल सुरंग का समर्थन करना चाहते हैं।

Answer 2

इसके अलावा, आप SSLSockerFactory के लिए योजना रजिस्टर करने की आवश्यकता:

httpClient.getConnectionManager().getSchemeRegistry().register(
    new Scheme("https", 443, SSLSocketFactory.getSystemSocketFactory()) 
);